Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:04Z
6n² + 4n + 1 = 0
ΔS ≥ 0
det| 7 8 ; 6 8 | = 8
122K
∫₀^∞ e^(-φ²) dφ = √π / 2
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-θ²) dθ = √π / 2
261K
d/dω [ω^10] = 10ω^9
∇²β = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O