Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:32Z
6n² + 4n + 1 = 0
∫₀^∞ e^(-t²) dt = √π / 2
278K
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
250K
\frac{2}{2} \sum_{i=1}^{n} i^{2}
261K
\frac{7}{1} \sum_{i=1}^{n} i^{2}
99K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
341K