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∇ × E = −∂B/∂t
d/dφ [φ^9] = 9φ^8
F = ma
iħ ∂ψ/∂t = Ĥψ
2y² + 6y + 5 = 0
REF https://commonchemistry.cas.org/
det| 8 7 ; 3 9 | = 51
11y² + 7y + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
E = mc²
12n² + 3n + 1 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
\frac{10}{8} \sum_{i=1}^{n} i^{2}
det| 7 3 ; 3 8 | = 47
∑_{k=1}^{n} k = n(n+1)/2
ΔS ≥ 0
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
\lim_{y\to 0} \frac{\sin y}{y} = 1
\frac{8}{4} \sum_{i=1}^{n} i^{2}
∇ × E = −∂B/∂t
ΔS ≥ 0
N₂ + 3H₂ ⇌ 2NH₃
d/dγ [γ^10] = 10γ^9
8t² + 5t + 5 = 0
\lim_{z\to 0} \frac{\sin z}{z} = 1
\oint_C \vec{F}\cdot d\vec{r} = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
e^{i\pi} + 1 = 0
e^{i\pi} + 1 = 0
det| 9 4 ; 3 10 | = 78
7ω² + 3ω + 0 = 0
F = G m₁m₂ / r²
E = mc²
F = ma
∂ω/∂ψ = 9ω
\oint_C \vec{F}\cdot d\vec{r} = 0
\lim_{x\to 0} \frac{\sin x}{x} = 1
∫₀^∞ e^(-x²) dx = √π / 2
ΔS ≥ 0
∂α/∂α = 2α
∑_{k=1}^{n} k = n(n+1)/2
REF https://math.stackexchange.com/
6γ² + 5γ + 3 = 0
2r² + 7r + 0 = 0
det| 5 3 ; 0 6 | = 30
d/dx [x^2] = 2x^1
Fe₂O₃ + 3CO → 2Fe + 3CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 11 1 ; 5 12 | = 127
REF https://oeis.org/
AgNO₃ + NaCl → AgCl↓ + NaNO₃
CH₄ + 2O₂ → CO₂ + 2H₂O
∇²φ = 0
d/dφ [φ^12] = 12φ^11
REF https://mathscinet.ams.org/
det| 4 5 ; 2 5 | = 10
E = mc²
d/dφ [φ^9] = 9φ^8
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
8r² + 7r + 1 = 0
det| 7 2 ; 6 8 | = 44
e^{i\pi} + 1 = 0
∇²n = 0
∇²t = 0
det| 11 3 ; 5 12 | = 117
\frac{9}{4} \sum_{i=1}^{n} i^{2}
det| 1 9 ; 3 2 | = -25
e^{i\pi} + 1 = 0
CaCO₃ → CaO + CO₂
d/dz [z^2] = 2z^1
CaCO₃ → CaO + CO₂
∫₀^∞ e^(-t²) dt = √π / 2
det| 9 8 ; 4 10 | = 58
REF https://pubchem.ncbi.nlm.nih.gov/
F = ma
∫₀^∞ e^(-t²) dt = √π / 2
N₂ + 3H₂ ⇌ 2NH₃
d/dα [α^9] = 9α^8
8r² + 2r + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
12β² + 6β + 0 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
PV = nRT
E = mc²
det| 3 6 ; 6 4 | = -24
\oint_C \vec{F}\cdot d\vec{r} = 0
REF https://en.wikipedia.org/wiki/Periodic_table
det| 11 4 ; 4 12 | = 116
CH₄ + 2O₂ → CO₂ + 2H₂O
∂α/∂r = 3α